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Cement volume: slurry, sacks, mix water and displacement

By the DrillPro team · Last reviewed 9 November 2026

A primary cement job has to put the right volume of slurry in the right place: enough to reach the planned top of cement, not so much that it is wasted or overloads a weak formation, and with the top plug landing on the float collar instead of being pumped past it. Every one of those outcomes comes down to a handful of capacity sums done before the job. This guide walks through them in the order a cementer or drilling engineer would, and finishes with a complete two-slurry example.

Where the slurry goes

Split the job into sections, because each one has a different capacity:

Capacity formulas

Annular capacity (bbl/ft) = (Hole or casing ID² − Casing OD²) ÷ 1029.4 Pipe or hole capacity (bbl/ft) = ID² ÷ 1029.4 Section volume (bbl) = Capacity × Length × (1 + Excess fraction)

Diameters are in inches. 1029.4 is the constant that turns inches squared into barrels per foot, so a 1 in ID holds 1 ÷ 1029.4 = 0.000971 bbl/ft. In metric units, capacity in m³/m is 0.7854 × (D² − d²) with diameters in metres.

Choosing the excess

Excess covers washouts, a hole drilled slightly over gauge, and slurry lost to the formation. Many operators use 20 to 50% over bit size in open hole when no caliper log is available, and less (often around 10 to 20%) over the caliper volume when one is. Soft or washed-out shale sections justify the higher end. Too much excess is not free: it raises the column height, the hydrostatic load on weak zones and the cost of the job.

From volume to sacks and water

The lab test for each slurry reports its density, its yield (the slurry volume one sack makes, in ft³/sk) and its mix water requirement (gal/sk). These depend on the cement class, additives and water ratio, so always take them from the lab sheet for your blend.

Slurry volume (ft³) = Slurry volume (bbl) × 5.615 Sacks = Slurry volume (ft³) ÷ Yield (ft³/sk) Mix water (bbl) = Sacks × Mix water (gal/sk) ÷ 42

For reference, neat Class G cement mixed at 15.8 ppg is commonly quoted at about 1.15 ft³/sk yield and about 5.0 gal/sk of water. Lightweight lead slurries with extenders yield much more per sack and need much more water.

Displacement

Once the slurry is pumped, the top plug is dropped and pushed down with mud or water until it lands (bumps) on the float collar. The displacement volume is the capacity of the casing from surface to the float collar, plus any surface lines that were not already full:

Displacement (bbl) = Casing ID² ÷ 1029.4 × Float collar depth (ft) Strokes = Displacement (bbl) ÷ Pump output (bbl/stk)

Use the actual ID of each casing weight in the string, not a nominal figure, and apply a realistic pump efficiency. Watch for the plug to bump near the calculated strokes. If it has not bumped by the calculated volume, many programs allow over-displacing by no more than about half the shoe track before stopping, so that cement around the shoe is not replaced by mud.

Worked example 1: slurry volumes for a 9-5/8 in string

9-5/8 in casing (47 lb/ft, ID 8.681 in) is run in 12-1/4 in hole to 8,000 ft, with 10 ft of rat hole below the shoe. The previous 13-3/8 in casing (ID 12.415 in) is set at 3,000 ft. The shoe track is 80 ft. Plan: tail slurry from the shoe to 6,500 ft, lead slurry from 6,500 ft to a top of cement at 2,500 ft (500 ft inside the 13-3/8 in). Use 30% excess in open hole and rat hole.

Open-hole annulus = (12.25² − 9.625²) ÷ 1029.4 = 0.0558 bbl/ft Overlap annulus = (12.415² − 9.625²) ÷ 1029.4 = 0.0597 bbl/ft Shoe track = 8.681² ÷ 1029.4 = 0.0732 bbl/ft Rat hole = 12.25² ÷ 1029.4 = 0.1458 bbl/ft Tail: open hole 1,500 ft × 0.0558 × 1.30 = 108.8 bbl shoe track 80 ft × 0.0732 = 5.9 bbl rat hole 10 ft × 0.1458 × 1.30 = 1.9 bbl Tail total = 116.5 bbl Lead: open hole 3,500 ft × 0.0558 × 1.30 = 253.8 bbl overlap 500 ft × 0.0597 = 29.9 bbl Lead total = 283.7 bbl

In metric terms that is about 18.5 m³ of tail and 45.1 m³ of lead (1 bbl = 0.159 m³).

Worked example 2: sacks, mix water and displacement

The lab sheet gives: tail, Class G at 15.8 ppg, yield 1.15 ft³/sk, mix water 4.97 gal/sk; lead, an extended blend at 12.8 ppg, yield 1.85 ft³/sk, mix water 10.0 gal/sk. The pump is a triplex with 6 in liners and a 12 in stroke at 97% efficiency.

Tail: 116.5 × 5.615 = 654.3 ft³ ÷ 1.15 = 569 sacks Mix water = 569 × 4.97 ÷ 42 = 67.3 bbl Lead: 283.7 × 5.615 = 1,592.8 ft³ ÷ 1.85 = 861 sacks Mix water = 861 × 10.0 ÷ 42 = 205.0 bbl Displacement = 0.0732 × (8,000 − 80) = 579.8 bbl Pump output = 0.000243 × 6² × 12 × 0.97 = 0.1018 bbl/stk Strokes = 579.8 ÷ 0.1018 ≈ 5,694 strokes

Half the shoe track is 40 ft × 0.0732 = 2.9 bbl, about 29 strokes, which is the most you would over-displace under the rule above if the plug has not bumped. Order bulk cement with a margin for dead volume in the silos and lines; the sack figures here are what ends up in the hole.

Mix water counts toward the water you must have available on location, but it is not the same as the slurry volume. The difference is the cement and additives themselves.

Practical checks

Before the job, compare the calculated slurry volume with a quick estimate from the annular capacity alone; an answer that is off by a factor of two usually means a wrong diameter or a dropped excess. Check the hydrostatic pressure of the full cement column plus spacer against the fracture pressure of the weakest zone, because a column that is too heavy causes losses and a low top of cement. During the job, track returns: if returns are lost while pumping slurry, the top of cement will be lower than planned and the excess was not enough.

Common mistakes

Work out hole and annular volumes in DrillPro

DrillPro does these sums for you on Android, the web and desktop, and exports the result to PDF or Excel.