Drilling guides › Hole volume, pipe capacity and annular capacity

Hole volume, pipe capacity and annular capacity

By the DrillPro team · Last reviewed 9 November 2026

Volumes decide how many strokes it takes to pump mud to the bit, how long bottoms-up takes and how much mud a trip needs. They all come from one simple formula. They also feed the kill sheet, the cement job and the pit volume you need on surface, so a small error here travels a long way.

Capacity of a hole or a pipe

Capacity (bbl/ft) = ID² (in) ÷ 1029.4 Capacity (L/m) = ID² (mm) ÷ 1273.2

Use the inside diameter of the pipe, or the bit size (or caliper size) for open hole. The constant 1029.4 comes from one barrel being 9,702 cubic inches: 9,702 ÷ (π/4 × 12 inches per foot) = 1029.4.

In other words, a one-foot slice of a cylinder holds π/4 × ID² × 12 cubic inches, and dividing by the cubic inches in a barrel turns that into barrels. The metric constant works the same way: 1273.2 is 4 ÷ π × 1,000, because a litre is a million cubic millimetres and a metre is a thousand millimetres.

Annular capacity

Annular capacity (bbl/ft) = (Hole ID² − Pipe OD²) ÷ 1029.4

Inside casing, use the casing ID instead of the bit size. Work each section separately (riser, casing, open hole; drill pipe, heavy-weight, collars) and add them up.

The annulus is simply the big circle minus the small one, so the squares are subtracted before dividing. Never subtract the diameters first: (8.5 − 5)² gives 12.25, not 47.25, and the volume would be wrong by a factor of almost four.

Worked example: 5 in drill pipe in 8½ in hole

ItemSumResult
Open hole 8.5 in8.5² ÷ 1029.40.0702 bbl/ft
5 in DP, ID 4.276 in4.276² ÷ 1029.40.0178 bbl/ft
Annulus 8.5 in × 5 in(72.25 − 25) ÷ 1029.40.0459 bbl/ft

With 10,000 ft of drill pipe (ignoring the BHA and casing to keep it short):

String volume = 0.0178 × 10,000 ≈ 178 bbl Annulus volume = 0.0459 × 10,000 ≈ 459 bbl Circulating volume (string + annulus) ≈ 637 bbl

In metric, the 8½ in (215.9 mm) hole holds 215.9² ÷ 1273.2 = 36.6 litres per metre.

Worked example: a well with casing and a BHA

Bit at 10,000 ft. 9⅝ in 47 lb/ft casing (ID 8.681 in) to 6,000 ft, then 8½ in open hole. String: 9,400 ft of 5 in drill pipe (ID 4.276 in) and 600 ft of 6½ in collars (ID 2.8125 in).

SectionCapacity (bbl/ft)Length (ft)Volume (bbl)
Casing × DP annulus(8.681² − 5²) ÷ 1029.4 = 0.04896,000293.5
Open hole × DP annulus0.04593,400156.1
Open hole × collars(72.25 − 42.25) ÷ 1029.4 = 0.029160017.5
Drill pipe bore0.01789,400167.0
Collar bore2.8125² ÷ 1029.4 = 0.00776004.6
Annulus = 293.5 + 156.1 + 17.5 = 467.1 bbl String = 167.0 + 4.6 = 171.6 bbl Total circulating volume ≈ 638.7 bbl

Notice how little the collars add to the string volume, and how much the casing section dominates the annulus. Shortcuts that treat the whole annulus as open hole would have underestimated it by about 18 bbl here, and more in a well with a longer casing string.

Steel displacement

Displacement is the volume of the steel itself: how much mud the pipe pushes out when it goes in the hole open-ended.

Displacement (bbl/ft) = (OD² − ID²) ÷ 1029.4

For 5 in pipe with a 4.276 in ID this gives 0.0065 bbl/ft for the tube alone. Tool joints add to it, so for trip sheets use the adjusted displacement from the pipe data sheet (often about 0.0075 bbl/ft for 5 in 19.5 lb/ft pipe).

Closed-end displacement

When the pipe is run with a float or pulled wet, the mud inside moves with it. The closed-end displacement is the steel displacement plus the pipe capacity, which is simply OD² ÷ 1029.4 (0.0243 bbl/ft for 5 in pipe, before tool joints).

Where these numbers are used

A useful cross-check

The volume of the hole with no pipe in it should equal the circulating volume plus the steel displacement of the string. In the casing-and-BHA example above, the empty hole holds 0.0732 × 6,000 + 0.0702 × 4,000 = 720 bbl. The tube displacement of the drill pipe (0.0065 × 9,400 ≈ 61 bbl) and the collars (0.0334 × 600 ≈ 20 bbl) adds 81 bbl to the 638.7 bbl circulating volume, giving the same 720 bbl. When the two sides do not match, one of the diameters or lengths in the table is wrong.

This empty-hole volume is also the mud the well needs when the string is out of the hole, which matters when planning a displacement to a new mud system or a weight-up with the pipe out.

Metric example

A 311 mm (12¼ in) hole with 127 mm (5 in) drill pipe has an annular capacity of (311.15² − 127²) ÷ 1273.2 ≈ 63.4 L/m. The oilfield figure, 0.1215 bbl/ft, multiplied by 521.6 (litres per metre in one bbl/ft) gives the same 63.4 L/m.

Common mistakes

Good practice

Real holes are bigger than the bit. When a caliper log or a known washout factor is available, use it for open hole volumes, cement and bottoms-up times. A 9.0 in average caliper in 8½ in hole raises the annular capacity around 5 in pipe from 0.0459 to 0.0544 bbl/ft, about 18 % more, or 34 bbl over 4,000 ft.

Open the hole volume calculator in DrillPro

DrillPro does these sums for you on Android, the web and desktop, and exports the result to PDF or Excel.